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Old 16 March 2011, 13:51   #11
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Country: UK - Scotland
Town: Stranraer
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Would expect output to be DC but you can only be certain with an Oscilloscope.
Can you see that output is coming from a rectifier? this would make it DC.
Is there not a circuit diagram in your handbook?

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Old 16 March 2011, 15:56   #12
Country: UK - Wales
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Measure the leads with the diode test function on your digital multimeter. you should measure open circuit one way, and about 1.2volts drop the otherway. this proves the presence of a rectifier voltage drop. if you get continuity both ways then its an AC output and needs a Rectifier adding. If its a low wattage output called a lighting output, then a regulator isnt nesscesary as the battery will clamp the voltage down to 15 volts maximum, as the battery reverse impedance falls rapidly at over this voltage.

I am usually not as green as i am cabbage looking.
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Old 16 March 2011, 16:14   #13
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You have AC power coming from under the flywheel, and (as i have not read all the answers etc) im guessing manual start engine? If its manual start you will have no regulator/rectifier fitted which you will need.

Outboards do have a very low output at tick over so to get round this you can fit a large capacitor to give you a better constant power. Really the best way to get regulated power would be to get the engine to charge a battery and run everything from the battery.
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Old 16 March 2011, 20:02   #14
Country: UK - Scotland
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Originally Posted by diver 1 View Post
The engines have the pre-described green wires coming out from beneath the flywheel these then link to a black box of electronic wizardry on the engine then continue to the battery...

When I use a voltmeter to check the voltage I get a reading of 26volts for AC and 14 volts for DC at fast tickover.

What is the best way to determine if it is DC or AC voltage? I only have a basic voltmeter...

I suspect you've got rectified AC but not voltage regulated. The rectifier effectively inverts the negative going part of the AC waveform so you have pulsing dc current. I think your meter is reading the peak voltage of the wave when set to AC and reading more of an average when set to dc. Since I have no knowledge of your meter, that's a best guess.

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